On 23 October in DR position LAT 21°13.0'N, LONG 152°18.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 259°psc. The chronometer reads 07h 21m 46s and is 01m 32s slow. Variation in the area is 5°E. What is the deviation of the magnetic compass?
Official USCG Answer & Rule Citation
Correct Answer: Option C — 5.9°W
Determine the Sun's declination for the date and the LHA using the corrected chronometer time. Calculate the True amplitude using the formula sin(Amp) = sin(Dec) / cos(Lat). The difference between the True bearing and the compass bearing (259°psc) yields the compass error; adjusting for 5°E variation results in 5.9°W deviation.
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