On 24 August in DR position LAT 26°49.4'N, LONG 146°19.4'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 084°psc. The chronometer reads 07h 55m 06s and is 01m 11s fast. Variation in the area is 15°W. What is the deviation of the magnetic compass?

Correct Answer: Option D — 8.3°E

Amplitude calculations use the declination from the Nautical Almanac and latitude to find the true bearing of the Sun at sunrise or sunset. Comparing computed true bearing with compass bearing and applying 15°W variation establishes a magnetic compass deviation of 8.3°E.