On 24 August in DR position LAT 26°49.4'N, LONG 146°19.4'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 084°psc. The chronometer reads 07h 55m 06s and is 01m 11s fast. Variation in the area is 15°W. What is the deviation of the magnetic compass?

Question

On 24 August in DR position LAT 26&deg;49.4'N, LONG 146&deg;19.4'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 084&deg;psc. The chronometer reads 07h 55m 06s and is 01m 11s fast. Variation in the area is 15&deg;W. What is the deviation of the magnetic compass?

Accepted Answer

Option B: 8.3&deg;E. Determine the Sun's declination for the date and the LHA using the corrected chronometer time. Calculate the True amplitude using the formula sin(Amp) = sin(Dec) / cos(Lat). The difference between the True bearing and the compass bearing yields the total compass error; subtracting variation from this error provides the magnetic deviation.