Navigation Problems USCG Question #540 (Set 16)

On 26 February your vessel's 1615 ZT DR position is LAT 25°14'S, LONG 57°22'W, when an azimuth of the Sun is observed. The chronometer time of the sight is 8h 13m 19s, and the Sun is bearing 266.0° per standard magnetic compass. The chronometer error is 01m 46s slow, and the variation in the area is 6°E. What is the deviation of the standard compass?

Official USCG Answer & Rule Citation

Correct Answer: Option C — 1.7°E

Calculate the Sun's true azimuth using the sight reduction tables or formulas based on LHA and Declination. Compare the True Azimuth (Zn) to the Compass Bearing (C) adjusted for variation. The difference between the True Bearing and the Magnetic Bearing (C + Var) provides the deviation, ensuring accurate compass correction.

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