On 26 September your 0830 DR position is LAT 26°04.0'N, LONG 129°16.0'W. Your vessel is on a course of 119°T at a speed of 20.0 knots. What is the zone time of local apparent noon (LAN)?
Official USCG Answer & Rule Citation
Correct Answer: Option A — 1124
Determine the longitude difference from the zone meridian (135°W). Apply the Equation of Time for 26 September. Account for the vessel's eastward movement toward the meridian. Using the standard formula for LAN, the time of meridian passage is calculated to be 1124 ZT.
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