Navigation Problems USCG Question #350 (Set 10)

On 26 September your 0830 zone time DR position is LAT 26°04.0'N, LONG 129°16.0'W. Your vessel is on course 119°T at a speed of 20.0 knots. What is the zone time of local apparent noon (LAN)?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 1124

Calculate the longitude difference from the zone meridian (135°W). Apply the Equation of Time for 26 September. The vessel's eastward movement toward the meridian advances the time of LAN. Following standard celestial navigation procedures, the vessel reaches the meridian at 1124 ZT.

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