On 27 June your 0734 zone time DR position is LAT 22°14.0'N, LONG 53°52.0'W. At that time, you observe the Sun bearing 069.5°psc. The chronometer reads 11h 32m 51s and the chronometer error is 01m 26s slow. The variation is 5°E. What is the deviation of the standard magnetic compass?

Question

On 27 June your 0734 zone time DR position is LAT 22&deg;14.0'N, LONG 53&deg;52.0'W. At that time, you observe the Sun bearing 069.5&deg;psc. The chronometer reads 11h 32m 51s and the chronometer error is 01m 26s slow. The variation is 5&deg;E. What is the deviation of the standard magnetic compass?

Accepted Answer

Option A: 1.6&deg;E. Find the Sun's True Azimuth (Zn) via the Nautical Almanac. Convert Zn to Magnetic Azimuth by applying Variation (5°E). Compare this to the Compass Bearing (069.5°psc). The difference indicates a deviation of 1.6°E, as the compass bearing is greater than the magnetic bearing.