On 3 October your 2122 ZT position is LAT 26°32'N, LONG 84°26'W. You observe Polaris bearing 359.8°pgc. At the time of the observation the helmsman noted that he was heading 106°pgc and 107°psc. The variation is 0°. What is the deviation for that heading?

Question

On 3 October your 2122 ZT position is LAT 26&deg;32'N, LONG 84&deg;26'W. You observe Polaris bearing 359.8&deg;pgc. At the time of the observation the helmsman noted that he was heading 106&deg;pgc and 107&deg;psc. The variation is 0&deg;. What is the deviation for that heading?

Accepted Answer

Option B: 0&deg;. Polaris azimuth correction is negligible at this latitude. Since the gyro bearing is 359.8° and the true bearing of Polaris is effectively 000°, the gyro error is 0.2°W. Given the variation is 0°, the deviation on the 106° heading is calculated as 0°.

On 3 October your 2122 ZT position is LAT 26&deg;32'N, LONG 84&deg;26'W. You observe Polaris bearing 359.8&deg;pgc. At the time of the observation the helmsman noted that he was heading 106&deg;pgc and 107&deg;psc. The variation is 0&deg;. What is the deviation for that heading?

On 3 October your 2122 ZT position is LAT 26°32'N, LONG 84°26'W. You observe Polaris bearing 359.8°pgc. At the time of the observation the helmsman noted that he was heading 106°pgc and 107°psc. The variation is 0°. What is the deviation for that heading?