On 4 October, your 0734 zone time DR position is LAT 24°11.0'N, LONG 162°34.0'E. At that time, you observe the Sun bearing 105.5°psc. The chronometer reads 08h 36m 11s, and the chronometer error is 01m 46s fast. The variation is 7°W. What is the deviation of the standard compass?

Correct Answer: Option D — 5.8°E

Apply chronometer error to the chronometer face to obtain UTC, then determine Local Hour Angle (LHA) using DR longitude. Enter navigational sight reduction tables with latitude and LHA to find computed azimuth (Zn). The angular difference between Zn and compass bearing yields error, which is cleared by variation to find deviation.