On 4 October, your 0734 zone time DR position is LAT 24°11.0'N, LONG 162°34.0'E. At that time, you observe the Sun bearing 105.5°psc. The chronometer reads 08h 36m 11s, and the chronometer error is 01m 46s fast. The variation is 7°W. What is the deviation of the standard compass?

Question

On 4 October, your 0734 zone time DR position is LAT 24&deg;11.0'N, LONG 162&deg;34.0'E. At that time, you observe the Sun bearing 105.5&deg;psc. The chronometer reads 08h 36m 11s, and the chronometer error is 01m 46s fast. The variation is 7&deg;W. What is the deviation of the standard compass?

Accepted Answer

Option D: 5.8&deg;E. Determine the Sun's true azimuth using the Nautical Almanac and Sight Reduction Tables. With a compass bearing of 105.5°psc and a variation of 7°W, the compass error is derived. Subtracting variation from the compass error (algebraically) yields a deviation of 5.8°E, satisfying the requirements for magnetic compass calibration.

On 4 October, your 0734 zone time DR position is LAT 24&deg;11.0'N, LONG 162&deg;34.0'E. At that time, you observe the Sun bearing 105.5&deg;psc. The chronometer reads 08h 36m 11s, and the chronometer error is 01m 46s fast. The variation is 7&deg;W. What is the deviation of the standard compass?

On 4 October, your 0734 zone time DR position is LAT 24°11.0'N, LONG 162°34.0'E. At that time, you observe the Sun bearing 105.5°psc. The chronometer reads 08h 36m 11s, and the chronometer error is 01m 46s fast. The variation is 7°W. What is the deviation of the standard compass?