Deck Misc (Supplementary) USCG Question #734 (Set 4)

On 5 June your 0420 zone time DR position is LAT 26°47.0' N, LONG 133°19.5' W. At that time, you observe Vega bearing 298.1°psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5°E. What is the deviation of the standard compass?

Official USCG Answer & Rule Citation

Correct Answer: Option C — 1.8°W

Determining standard compass deviation requires calculating the true azimuth of Vega using GMT, Almanac data, and the navigational triangle. Comparing true bearing to compass bearing yields magnetic bearing. Applying chart variation to magnetic bearing isolates the remaining standard compass deviation of 1.8°W.

100% Free & Open Access — No daily limits, paywalls, or gated answers on BrightMariner.
Back to Deck Misc (Supplementary) Sets