On 5 June your 0420 zone time DR position is LAT 26°47.0'N, LONG 133°19.5'W. At that time, you observe Vega bearing 298.1°psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5°E. What is the deviation of the standard compass?

Question

On 5 June your 0420 zone time DR position is LAT 26&deg;47.0'N, LONG 133&deg;19.5'W. At that time, you observe Vega bearing 298.1&deg;psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5&deg;E. What is the deviation of the standard compass?

Accepted Answer

Option C: 1.8&deg;W. Establish exact GMT from chronometer data, query Almanac for Vega's coordinates, and solve the PZX triangle via Bowditch methods. Compare the computed true bearing with standard compass observations and variation to compute deviation.

On 5 June your 0420 zone time DR position is LAT 26&deg;47.0'N, LONG 133&deg;19.5'W. At that time, you observe Vega bearing 298.1&deg;psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5&deg;E. What is the deviation of the standard compass?

On 5 June your 0420 zone time DR position is LAT 26°47.0'N, LONG 133°19.5'W. At that time, you observe Vega bearing 298.1°psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5°E. What is the deviation of the standard compass?