On 5 September in DR position LAT 23°17.0'S, LONG 154°35.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 275° per standard magnetic compass. The chronometer reads 07h 49m 26s and is 01m 52s fast. Variation in the area is 3°W. What is the deviation of the standard magnetic compass?

Correct Answer: Option A — 5.1°E

Determine the Sun's declination for the date and time. Calculate the True Amplitude using the formula sin(Amp) = sin(Dec) / cos(Lat). Comparing the True Amplitude to the compass bearing provides the Compass Error. Subtracting the 3°W variation from the Compass Error results in a deviation of 5.1°E.