Navigation Problems USCG Question #1575 (Set 47)

On 5 September in DR position LAT 23°17.0'S, LONG 154°35.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 275° per standard magnetic compass. The chronometer reads 07h 49m 26s and is 01m 52s fast. Variation in the area is 3°W. What is the deviation of the standard magnetic compass?

Official USCG Answer & Rule Citation

Correct Answer: Option C — 5.1°E

Calculate the Sun's declination and LHA using the Nautical Almanac. Determine the true amplitude (sin Amp = sin Dec / cos Lat). Compare the true amplitude to the compass amplitude (275°). Applying variation (3°W) to the true bearing yields a deviation of 5.1°E.

100% Free & Open Access — No daily limits, paywalls, or gated answers on BrightMariner.
Back to Navigation Problems Sets