On 6 August your 1552 zone time DR position is LAT 24°26.0'S, LONG 73°19.0'E. At that time, you observe the Sun bearing 302°psc. The chronometer reads 10h 55m 07s, and the chronometer error is 02m 38s fast. The variation is 6°E. What is the deviation of the standard magnetic compass?

Correct Answer: Option B — 6.1°W

Universal Time from chronometer corrected for error enables entering the Nautical Almanac and Sight Reduction Tables to find the Sun's true azimuth. Comparing true bearing against compass bearing through standard error analysis determines magnetic compass deviation of 6.1°W.