On 6 November your 0752 zone time DR position is LAT 25°11.0'N, LONG 76°07.0'W. At that time, you observe the Sun bearing 119°psc. The chronometer reads 12h 53m 07s, and the chronometer error is 01m 19s fast. The variation is 3°W. What is the deviation of the standard magnetic compass?

Question

On 6 November your 0752 zone time DR position is LAT 25&deg;11.0'N, LONG 76&deg;07.0'W. At that time, you observe the Sun bearing 119&deg;psc. The chronometer reads 12h 53m 07s, and the chronometer error is 01m 19s fast. The variation is 3&deg;W. What is the deviation of the standard magnetic compass?

Accepted Answer

Option D: 3.2&deg;E. Calculate the Sun's declination and LHA using the corrected GMT. Determine the True amplitude using sin(Amp) = sin(Dec) / cos(Lat). The difference between the True bearing and the compass bearing (119°) provides the compass error. Applying the 3°W variation to this error results in a deviation of 3.2°E.