Navigation Problems USCG Question #1621 (Set 48)

On 6 October your 0416 zone time DR position is LAT 25°16.0'N, LONG 130°25.0'E. At that time, you observe Mars bearing 083°psc. The chronometer reads 07h 16m 22s, and the chronometer error is 00m 10s fast. The variation is 1.5°E. What is the deviation of the standard compass?

Official USCG Answer & Rule Citation

Correct Answer: Option B — 1.2°W

Calculate the true azimuth of Mars using the Nautical Almanac. Comparing the true azimuth to the compass bearing of 083°psc provides the compass error. Applying the variation of 1.5°E to the compass error formula (Error = Var + Dev) results in a deviation of 1.2°W, confirming the vessel's magnetic signature.

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