On 8 December in DR position LAT 21°56.1'S, LONG 17°21.6'E you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 240.5°psc. The chronometer reads 05h 27m 21s and is 00m 47s fast. Variation in the area is 3.3°E. What is the deviation of the standard magnetic compass?

Correct Answer: Option D — 1.5°E

Determine the Sun's declination and calculate the True Amplitude. The difference between the True Amplitude and the compass bearing provides the Compass Error. Applying the 3.3°E variation to the Compass Error results in a deviation of 1.5°E, adhering to the standard celestial navigation process for compass calibration.