On 8 December in DR position LAT 21°56.1'S, LONG 17°21.6'E you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 240.5°psc. The chronometer reads 05h 27m 21s and is 00m 47s fast. Variation in the area is 3.3°E. What is the deviation of the standard magnetic compass?
Official USCG Answer & Rule Citation
Correct Answer: Option D — 1.5°E
Calculate the Local Apparent Time (LAT) using the chronometer time and longitude to find the Sun's declination and LHA. Using the amplitude formula, sin(Amp) = sin(Dec) / cos(Lat), determine the True bearing. Compare the True bearing to the compass bearing to find Compass Error, then apply variation to isolate deviation.
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