Navigation Problems USCG Question #1615 (Set 48)

On 9 February your 0739 zone time DR position is LAT 23°31.0'N, LONG 143°41.0'E. At that time, you observe the Sun bearing 104.5°psc. The chronometer reads 09h 37m 12s, and the chronometer error is 01m 52s slow. The variation is 3.5°W. What is the deviation of the standard magnetic compass?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 8.6°E

Calculate the Sun's declination for 9 February. Determine the true amplitude using sin(Amp) = sin(Dec) / cos(Lat). Convert the true amplitude to a true bearing. Apply the 3.5°W variation to the compass bearing of 104.5°psc to find the magnetic bearing. The difference between true and magnetic bearings results in 8.6°E deviation.

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