On 9 May your vessel's 1809 ZT DR position is LAT 48°13.7'N, LONG 168°36.3'E, when an amplitude of the Sun is observed. The Sun's center is on the celestial horizon and bears 283.7° per standard magnetic compass. Variation in the area is 13.0°E. The chronometer reads 07h 13m 19s and is 02m 56s fast. What is the deviation of the standard compass?
Official USCG Answer & Rule Citation
Correct Answer: Option A — 0.1°W
Find the Sun's declination using the Nautical Almanac. Calculate the true amplitude using the formula sin(Amp) = sin(Dec) / cos(Lat). Comparing the true amplitude to the magnetic bearing of 283.7° and applying the 13.0°E variation yields a deviation of 0.1°W.
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