The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 40,301 foot-long tons, TM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the uncorrected height of the center of gravity?

Correct Answer: Option B — 53.78 feet

Uncorrected vertical center of gravity (KG) is determined by dividing total vertical moments (VM) by total displacement. Utilizing the provided VM of 974,441 foot-long tons and vessel displacement parameters yields an uncorrected KG of 53.78 feet, per standard MODU stability calculation methods.