The liquid mud tanks on your vessel measure 22'L by 16'B by 7'D. The vessel's displacement is 568 T and the specific gravity of the mud is 1.6. What is the reduction in GM due to a pair of these tanks (p/s) being slack?

Correct Answer: Option C — 1.18 feet

The reduction in GM is calculated using the formula FSC = (l * b^3 * sg_liquid) / (12 * Displacement). For two tanks, the formula is doubled. Using 22'x16'x7', sg 1.6, and 568 tons displacement, the calculation (2 * (22 * 16^3 * 1.6) / (12 * 568)) results in 1.18 feet.