The liquid mud tanks on your vessel measure 24'L by 16'B by 8'D. The vessel's displacement in fresh water is 864 tons and the specific gravity of the mud is 1.47. What is the reduction in GM due to a pair of these tanks (p/s) being slack?

Correct Answer: Option B — .80 foot

FSC = (l * b^3 * sg_liquid) / (12 * Displacement * sg_vessel). For a pair of tanks, multiply the result by two. With dimensions 24'x16'x8', sg 1.47, and 864 tons displacement, the calculation (2 * (24 * 16^3 * 1.47) / (12 * 864)) yields a reduction of 0.80 feet.