Safety & Environmental Protection (Deck) USCG Question #3013 (Set 85)

To check stability, a weight of 10 tons is lifted with the jumbo boom whose head is 45 ft. from the ship's centerline. The clinometer show's a list of 5.0° with weight suspended. Displacement including the weight is 9,000 tons. What would be the GM in this condition?

Official USCG Answer & Rule Citation

Correct Answer: Option A — 0.57 foot

Calculate the metacentric height using the formula GM = (w * d) / (Displacement * tan(theta)). Substituting the values: (10 tons * 45 feet) / (9000 tons * tan(5.0 degrees)) = 450 / (9000 * 0.08749) = 450 / 787.4 = 0.571 feet. This result represents the vessel's stability during the specific heavy lift condition described.

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