To check stability, a weight of 35 tons is lifted with the jumbo boom, whose head is 35 feet from the ship's centerline. The clinometer shows a list of 7.0° with the weight suspended. Displacement including the weight is 14,000 tons. What would the length of GM in this condition?

Question

Accepted Answer

Option A: 0.71 foot. Suspended weight stability calculations use the formula GM = (w * d) / (W * tan(list)). With a 35-ton weight, 35-foot boom radius, 14,000-ton displacement, and 7-degree list, the resulting metacentric height is precisely 0.71 foot.