To check stability, a weight of 35 tons is lifted with the jumbo boom, whose head is 35 feet from the ship's centerline. The clinometer shows a list of 7.0° with the weight suspended. Displacement including the weight is 14,000 tons. What would the length of GM in this condition?
Official USCG Answer & Rule Citation
Correct Answer: Option A — 0.71 foot
The metacentric height is determined by the formula GM = (w * d) / (Displacement * tan(theta)). Substituting the provided values: (35 tons * 35 feet) / (14000 tons * tan(7.0 degrees)) = 1225 / (14000 * 0.12278) = 1225 / 1718.9 = 0.712 feet. This calculation confirms the vessel's stability condition during the heavy lift operation.
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