Safety & Environmental Protection (Deck) USCG Question #2402 (Set 73)

To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5° with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?

Official USCG Answer & Rule Citation

Correct Answer: Option C — 0.88 foot

Metacentric height is calculated using the formula GM = (w * d) / (W * tan(list)). Substituting the values yields GM = (40 * 40) / (16000 * tan(6.5°)), resulting in 0.88 foot, which properly accounts for the suspended weight shift effect on vessel stability.

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