What is the new location of the transverse center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and displacement 9,000 short tons?

Correct Answer: Option A — 0.47 foot starboard of centerline

Transverse center of gravity is determined by taking moments about the centerline. The initial moment is 9,000 tons times 0.7 ft starboard (+6,300 ft-tons). Adding 200 tons at 10 ft port (-2,000 ft-tons) yields a new net moment of +4,300 ft-tons divided by the new displacement of 9,200 tons, resulting in 0.47 ft starboard.