What is the transverse shift in the center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and the displacement is 9,000 short tons?

Correct Answer: Option C — 0.23 foot

Transverse shift of the center of gravity is calculated by multiplying the weight moved by the transverse distance, divided by total displacement. Weight of 200 short tons moved 10 feet divided by 9,000 tons displacement results in a direct transverse shift of 0.23 foot.