You are making a heavy lift with the jumbo boom. Your vessel displaces 8390 T. The 40 ton weight is on the pier and its center is 55' to starboard of the centerline. The head of the boom is 110' above the base line and the center of gravity of the lift when stowed on deck will be 45' above the base line. As the jumbo boom takes the strain the ship lists to 3.5°. What is the GM with the cargo stowed?
Official USCG Answer & Rule Citation
Correct Answer: Option A — 4.58 feet
Using standard stability principles for jumbo boom operations, initial list when taking strain on the pier weight allows determination of virtual rise in G. Final GM calculation yields 4.58 feet based on 8390 tons displacement and a 3.5-degree list.
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