Safety & Environmental Protection (Deck) USCG Question #2399 (Set 73)

You are making a heavy lift with the jumbo boom. Your vessel displaces 7940 T. The 45-ton weight is on the pier and its center is 60' to starboard of the centerline. The head of the boom is 110' above the base line and the center of gravity of the lift when stowed on deck will be 50' above the base line. As the jumbo boom takes the strain the ship lists to 4.5°. What is the GM with the cargo stowed?

Official USCG Answer & Rule Citation

Correct Answer: Option B — 4.64

Jumbo boom heavy lift procedures require calculating the initial list moment to find the virtual center of gravity. Using 7940 tons displacement, 45-ton lift, and 4.5-degree list determines the correct stowed GM of 4.64 ft.

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