You are on a great circle track departing from LAT 25°50.0'N, LONG 77°00.0'W and your initial course is 061.7°T. The position of the vertex is LAT 37°35.6'N, LONG 25°57.8'W. What is the distance along the great circle track between the point of departure and the vertex?

Question

You are on a great circle track departing from LAT 25&deg;50.0'N, LONG 77&deg;00.0'W and your initial course is 061.7&deg;T. The position of the vertex is LAT 37&deg;35.6'N, LONG 25&deg;57.8'W. What is the distance along the great circle track between the point of departure and the vertex?

Accepted Answer

Option B: 2664.9 miles. Using the Napier’s Rules for right spherical triangles, the distance from the point of departure to the vertex is found via the formula cos(Dist) = cos(Lat1) * sin(Initial Course). Applying the given coordinates and course, the calculated great circle distance to the vertex is 2664.9 miles.

You are on a great circle track departing from LAT 25&deg;50.0'N, LONG 77&deg;00.0'W and your initial course is 061.7&deg;T. The position of the vertex is LAT 37&deg;35.6'N, LONG 25&deg;57.8'W. What is the distance along the great circle track between the point of departure and the vertex?

You are on a great circle track departing from LAT 25°50.0'N, LONG 77°00.0'W and your initial course is 061.7°T. The position of the vertex is LAT 37°35.6'N, LONG 25°57.8'W. What is the distance along the great circle track between the point of departure and the vertex?