You are underway on course 215°T at 12 knots. The current is 000°T at 2.3 knots. What is the course made good?

Correct Answer: Option A — 222°T

Apply vector addition by plotting the ship's course and speed vector (215°T, 12 knots) and the current vector (000°T, 2.3 knots). The resultant vector represents the course made good. Calculating the triangle of velocities confirms the track over ground is 222°T, accounting for the set and drift.