You have approximately 14 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 6 feet? (total displacement is 210 tons)

Correct Answer: Option D — 0.4 foot

Using the fundamental stability equation $\Delta KG = (w \times d) / W$, multiplying 14 tons by the 6-foot vertical distance and dividing by the 210 tons total displacement yields a 0.4 foot shift.