You have approximately 15 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 300 tons)

Correct Answer: Option A — 0.4 foot

The vertical shift of the center of gravity ($\Delta KG$) is calculated using the formula $\Delta KG = (w \times d) / W$. Multiplying 15 tons by the 8-foot distance and dividing by the total displacement of 300 tons yields 0.4 foot downward.