You have approximately 16 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 640 tons)
Official USCG Answer & Rule Citation
Correct Answer: Option B — 0.2 foot
To find the shift in the center of gravity, use $\Delta KG = (w \times d) / W$. Multiplying 16 tons by 8 feet and dividing by 640 tons total displacement calculates exactly to a 0.2 foot shift.
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