You have approximately 24 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 540 tons)

Correct Answer: Option A — 0.36 foot

Calculating the vertical gravity shift via $\Delta KG = (w \times d) / W$, multiplying 24 tons by the 8-foot distance, then dividing by the 540 tons total displacement, gives 0.355, rounding to 0.36 foot.