You have approximately 60 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 960 tons)

Correct Answer: Option A — 0.5 foot

Using the standard shifting formula $\Delta KG = (w \times d) / W$, multiplying 60 tons by the 8-foot distance and dividing by the 960 tons total displacement produces a vertical center of gravity shift of 0.5 foot.