Navigation Problems USCG Question #349 (Set 10)

Your 0900 DR position is LAT 23°16'N, LONG 146°12'E. Your vessel is on a course of 286°T, at a speed of 14.5 knots. Determine the zone time of LAN on 14 March.

Official USCG Answer & Rule Citation

Correct Answer: Option C — 1228

Calculate the longitude difference from the zone meridian (150°E). Apply the Equation of Time for 14 March. The vessel's westward movement delays the time of LAN. Following the standard celestial navigation procedures outlined in Bowditch, the vessel reaches the meridian at 1228 ZT.

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