Your vessel departs Arkhangel'sk, from position LAT 64°32'N, LONG 40°31'E at 0236 zone time, on 19 August. It is bound for New York, at position LAT 40°42'N, LONG 74°01'W. The distance is determined to be 4,216 miles, and you estimate that you will average 13.0 knots. What is your estimated zone time of arrival?

Question

Your vessel departs Arkhangel'sk, from position LAT 64&deg;32'N, LONG 40&deg;31'E at 0236 zone time, on 19 August. It is bound for New York, at position LAT 40&deg;42'N, LONG 74&deg;01'W. The distance is determined to be 4,216 miles, and you estimate that you will average 13.0 knots. What is your estimated zone time of arrival?

Accepted Answer

Option C: 0655, 1 September. Divide the total distance (4,216 nm) by the speed (13.0 knots) to find a transit time of 324.3 hours (13 days, 12 hours, 18 minutes). Adjusting for the zone time difference between ZD -3 and ZD +5 (8 hours) and adding to the departure time yields 0655 on 1 September.