Your vessel displaces 10,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 45° if the center of gravity shifts 2.0 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Question

Accepted Answer

Option B: 2.7 feet. Obtain the 45° uncorrected righting arm from the blue pages for a 10,000-ton displacement and 22.6-foot KG. Deduct the transverse weight shift reduction ($2.0 	imes \sin 45°$) to arrive at the correct remaining righting arm of 2.7 feet.