Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30° if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)
Official USCG Answer & Rule Citation
Correct Answer: Option A — 0.8 foot
Find the base righting arm at 30° inclination for a displacement of 12,000 tons and KG of 22.6 feet. Subtract the transverse stability reduction ($1.8 \times \sin 30°$) to determine the final remaining righting arm value of 0.8 foot.
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