Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30° if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Question

Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30&deg; if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Accepted Answer

Option A: 0.8 foot. The remaining righting arm is calculated by subtracting the transverse shift effect (GG' * cos(theta)) from the initial righting arm (GZ) found in the stability curves. At 30 degrees, the correction is 1.8 * cos(30). Subtracting this from the curve's GZ value yields 0.8 feet.

Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30&deg; if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30° if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)