Your vessel displaces 9,000 tons and has a KG of 21.2 feet. What will be the length of the remaining righting arm at an angle of inclination of 30° if the center of gravity shifts 2.6 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Question

Accepted Answer

Option D: 1.4 feet. Locate the 30° uncorrected righting arm for a 9,000-ton displacement and 21.2-foot KG. Subtract the transverse center of gravity shift reduction ($2.6 	imes \sin 30°$) to accurately calculate the remaining righting arm of 1.4 feet.