Your vessel is on a course of 103°T at 14 knots. At 1918 a light bears 129.5°T, and at 1937 the light bears 148°T. At what time and at what distance off will your vessel be when abeam of the light?

Question

Your vessel is on a course of 103&deg;T at 14 knots. At 1918 a light bears 129.5&deg;T, and at 1937 the light bears 148&deg;T. At what time and at what distance off will your vessel be when abeam of the light?

Accepted Answer

Option B: 1956, 4.4 miles. Applying the 'doubling the angle on the bow' principle, the time to run between bearings equals the time to reach the abeam position. With a 19-minute interval between bearings, adding 19 minutes to 1937 gives 1956. Distance off is calculated using the speed and time run.

Your vessel is on a course of 103&deg;T at 14 knots. At 1918 a light bears 129.5&deg;T, and at 1937 the light bears 148&deg;T. At what time and at what distance off will your vessel be when abeam of the light?

Your vessel is on a course of 103°T at 14 knots. At 1918 a light bears 129.5°T, and at 1937 the light bears 148°T. At what time and at what distance off will your vessel be when abeam of the light?