Your vessel is preparing to lift a weight of 30 tons with a boom whose head is 30 feet from the ship's centerline. The ship's displacement not including the weight lifted is 8,790 tons. KM is 21.5 ft, KG is 20.5 ft. What would be the angle of list when the weight is lifted?

Question

Your vessel is preparing to lift a weight of 30 tons with a boom whose head is 30 feet from the ship's centerline. The ship's displacement not including the weight lifted is 8,790 tons. KM is 21.5 ft, KG is 20.5 ft. What would be the  angle of list when the weight is lifted?

Accepted Answer

Option D: 5.8°. Lifting a weight with a shipboard boom creates an immediate virtual rise in the center of gravity. The angle of list is determined using the formula: Tan(list) = (weight × distance from centerline) / (displacement × GM). Substituting the given values results in a 5.8° list.