Your vessel is preparing to lift a weight of 30 tons with a boom whose head is 30 feet from the ship's centerline. The ship's displacement not including the weight lifted is 8,790 tons. KM is 21.5 ft, KG is 20.5 ft. What would be the angle of list when the weight is lifted?

Question

Accepted Answer

Option D: 5.8&deg;. List angle is calculated using the formula: Tan(List) = (w * d) / ((Displacement + w) * GM). With w = 30 tons, d = 30 ft, Displacement = 8790 tons, and GM = KM - KG = 1.0 ft, the resulting angle evaluates to approximately 5.8 degrees.