What will be the resulting current when a voltage of 110 VDC is applied to a resistance of 32 ohms in figure "A" of the illustrated circuit when the switch is closed? Illustration EL-0018

Correct Answer: Option D — 3.44 amps

Applying Ohm's Law where current equals voltage divided by resistance ($I = V / R$), dividing 110 volts DC by 32 ohms yields exactly 3.4375 amps, which rounds to 3.44 amps of current flowing through the closed circuit.