What would be the actual rotor speed for a 4-pole three-phase squirrel-cage induction motor operating at 60 Hz if the rotor slip is 3%?
Official USCG Answer & Rule Citation
Correct Answer: Option A — 1746 rpm
Actual rotor speed accounts for slip: $N_r = N_s \times (1 - \text{slip})$. Synchronous speed for a 4-pole, 60 Hz motor is 1800 rpm. Applying 3% slip yields $1800 \times (1 - 0.03) = 1746\text{ rpm}$. IEEE 45 governs induction motor performance calculations for marine auxiliary systems.
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